The number of unit cells in `58.5 g` of `NaCl` is nearly

Options

A. `6 xx 10^(20)`
B. `3 xx 10^(22)`
C. `1.5 xx 10^(23)`
D. `0.5 xx 10^(24)`

Answer

c

Explanation

`58.8 g NaCI= 1` mole `= 6.02 xx 10^(25) NaCI `unit one unit cell contants `4Na^(+)CVI^(-)` unit hence number of unit cell present
`= (6.02 xx 10^(23))/(4) = 1.5 xx 10^(23)`.