In solid oxide are arranged in cup .One - sixth of tetrabedral voids are occupied by cation A which one third of octahedral voids are occupied by cation `B` .What is the formula of compound ?

Options

A. `AB_(2)O`
B. `ABO_(3)`
C. `A_(2)B_(3)O`
D. `A_(3)B_(2)O`

Answer

B

Explanation

Suppose `O^(2) `ions `+n`, octabedral voids interecdral voids
` = 2n,cation A = (1)/(6) xx 2n = (n)/(3)`
`Cation B = (1)/(3) xx n = (n)/(3)`
`Ratio - A: B: O^(2)`
`= (n)/(3) (n)/(3) :n`
Formulas`ABO_(3)`