An element (atomic mass `= 100 g//mol`) having bcc structure has unit cell edge 400 pm .Then density of the element is

Options

A. `10.376 g//cm^(3)`
B. `2.144 g//cm^(3)`
C. `7.289 g//cm^(3)`
D. `5.188 g//cm^(3)`

Answer

d

Explanation

`rho = (n xx M)/(a^(3) xx N_(0) xx 10^(-30)) = (2 xx 100)/((400)^(3) xx (6.02 xx 10^(23)) xx 10^(-30))`
`= 5.188 g//cm^(2)`