Home
Class 12
CHEMISTRY
The differaction of barium with X-cadiat...

The differaction of barium with X-cadiation of wavelength `227` pm given a first - order differaction at `30^(@)` .Thus , distance between the two plannes is

A

`114.5` pm

B

`229` pm

C

`458` pm

D

`227` pm

Text Solution

Verified by Experts

The correct Answer is:
d
By Bragg's equation
` 2a sin theta = n lambda`
`n = 1` (first order difference)
` lambda = 229` pm
`sin theta = sin 30^(@) = (1)/(2)`
`a = (n lambda)/( 2sin theta) = (1 xx 217 "pm")/(2 xx (1)/(3)) = 227` pm
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    A2Z|Exercise Section B - Assertion Reasoning|21 Videos

  • SOLID STATE

    A2Z|Exercise AIPMT/NEET Questions|23 Videos

  • SOLID STATE

    A2Z|Exercise Defects In Solids And Semiconductors|21 Videos

  • P BLOCK ELEMENTS ( GROUP 15,16,17,18)

    A2Z|Exercise Section D - Chapter End Test|30 Videos

  • SOLUTIONS

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

Monochromatic X-rays, when reflected from a crystal with lattice spacing 2.0 Å , produce first order diffraction maximum at theta=30^(@) . What is the wavelength of X-rays ?

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60^(@) and the angle of elevation of the top of the second tower from the foot of the first tower is 30^(@) . Find the distance between the two towers and also the height of the other tower.

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60^@ and the angle of elevation of the top iof the second tower from the foot of the first tower is 30^@ . The distance between the two towers isntimes the height of the shorter tower. What is nequal to?

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60^(@) and the angle of elevation of the top of the second tower from the foot of the first tower is 30^(@) . Find the distance between the two and also the height of the tower.

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60^(@) and the angle of elevation of the top of the second tower from the foot of the first tower is 30^(@). The distance between the two towers is m times the height of the shorter tower. What is m equal to ?

Two wavelengths of sodium light 590 nm and 596 nm are used, in turn, to study the diffraction taking place at a single slit of aperature 2 xx 10^(-4) m . The distance between the slit and the screen is 1.5 m. Calcualate the separation between the positions of first maximum of the diffractions patterns obtained in two cases.

In a Young's double-slit experiment, if the incident light consists of two wavelengths lambda_(1) and lambda_(2) , the slit separation is d, and the distance between the slit and the screen is D, the maxima due to each wavelength will coincide at a distance from the central maxima, given by

A sample of a crystalline solid scatters a beam of X-rays of wavelength 70.93 pm at an angle 2 theta of 14.66^(@) . If this is a second-order reflection (n = 2), calculate the distance between the parallel planers of atoms from which the scattered beam appears to have been reflected.

In a Young's double slit experiment, if the incident light consists of two wavelengths lamda_(1)andlamda_(2) , the slit separation is d, and the distance between the slit and the screen is D, the maxima due to the two wavelengths will coincide at a distance from the central maxima, given by :