The rate constant fro a second order reaction is `8 xx 10^(-5) M^(-1) "min"^(-1)`. How long will in take a `1 M` solution to be reduced to `0.5 M`

Options

A. `8 xx 10^(-5) min`
B. `8.665 xx 10^(3) min`
C. `4 xx 10^(-5) min`
D. `1.25 xx 10^(4) min`

Answer

D

Explanation

`8 xx 10^(-5) = (1)/(t)[(1)/(0.5) - (1)/(1)], 8 xx 10^(5) = (1)/(t) [2 - 1]`
`t = (1)/(8 xx 10^(-5)) = 0.125 xx 10^(5) = 1.25 xx 10^(4) min`