If the rate constant for the disintegration of a radioactive nucleus is `lambda`. Therefore the probability, `P` of survival of a radioactive nucleus for one mean life is

Options

A. `e`
B. ( b) `e^(2)`
C. `e^(-1)`
D. `e^(-2)`

Answer

C

Explanation

Probability for survival `= (N)/(N_(0)) = e^(-lambda ul(t))`
Now mean life period `= (1)/(lambda)`
`:.` Probability `= e ^(-lambda xx (1)/(lambda)) = e^(-1)`