For a certain reaction the variation of rate constant with temperature is given by the equation
`ln k_(t) = lnk_(0) + ((ln 3)t)/(10) (t ge 0^(@)C)`
The value of temperature coefficient of the reaction is

Options

A. `0.1`
B. `1`
C. `10`
D. `3`

Answer

D

Explanation

`(k_(1))/(k_(0)) = mu^((t-0)/(10))`
`log_(e) k_(t) -loge k_(0)= (t)/(10) log(mu)`
`ln k_(t) = ln k_(0) + ((ln(mu))/(10)) t`
`mu = 3`.