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If a I-order reaction is completed to th...

If a I-order reaction is completed to the extent of `60%` and `20%` in time intevals, `t_(1)` and `t_(2)`, what is the ratio, `t_(1) : t_(2)`?

A

`6.32`

B

`5.58`

C

`4.11`

D

`8.33`

Text Solution

Verified by Experts

The correct Answer is:
C
`t_(1) = (2.303)/(K)"log"((100)/(40))`…(1)
`t_(2) = (2.303)/(K)"log"((100)/(80))`…(2)
From (1) and (2) `(t_(1))/(t_(2)) = 4.11`
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