The experiment data for the reaction `2A + B_(2) rarr 2AB` is
`|{:("Experiment",[A] M,[B_(2)] M,"Initial rate" (mol L^(-1) s^(-1)),),(I,0.50,0.5,1.6 xx 10^(-4),),(II,0.50,1.0,3.2 xx 10^(-4),),(III,1.00,1.0,3.2 xx 10^(-4),):}|`
Write the most probable rate equation for the reacting giving reason for you answer.

Options

A. rate `= k[B_(2)]^(2)`
B. rate `= k[B]`
C. rate `= k[A]^(2)[B]^(2)`
D. ( d) rate `= k[A]^(2)[B]`

Answer

B

Explanation

`r = k[A]^(x)[B]^(y)`
`1.6 xx 10^(-4) = k[0.5]^(x)[0.5]^(y)` …(1)
`3.2 xx 10^(-4) = k[0.5]^(x)[1.0]^(y)` …(2)
`3.2 xx 10^(-4) = k[1.0]^(x)[1.0]^(y)`…(3)
`{:((2)-:(1),,,2=2yrArry=1,),((3)-:(2),,,1=2xrArrx=0,),(,,,r=k[A]^(@)[B]^(1) rArr r=K[B],):}`