For the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the rate of reaction is expressed as

Options

A. `(-d[H_(2)])/(dt) = (-d[I_(2)])/(dt) = (-d[HI])/(dt)`
B. `(d h_(2))/(d t) = (d[I_(2)])/(d t) = (d[HI])/(d t)`
C. `(1)/(2)(d[H_(2)])/(d t) = (1)/(2)(d[I_(2)])/(d t) = (-d[HI])/(d t)`
D. `-2(d[H_(2)])/(d t) = -2(d[I_(2)])/(d t) = (d[HI])/(d t)`

Answer

D

Explanation

`(d[H_(2)])/(d t) = (+d[I_(2)])/(d t) = (-1)/(2)(d[HI])/(d t)`