Two reactions `A rarr` products and `B rarr` products have rate constants `k_(a)` and `k_(b)` respectively at temperature `T` and activation energies are `E_(a)` and `E_(b)` respectively.
If `k_(a) gt k_(b)` and `E_(a) lt E_(b)` and assuming the freuency factor `A` in both the reactions are same then

Options

A. on increasing temperature `k_` will be greater than `k_(b)`
B. At lower temperature `k_(a)` and `k_` will differ more
C. As temperature rises `k_(a)` and `k_(b)` will be close to each other in magnitude
D. All of the above are correct

Answer

D

Explanation

ln `k_(a) = A - E_(a)//RT`, ln `k_(b) = A - E_(b)//RT`
As temperature rises `E//RT` become negligible.