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KMnO(4) in basic medium is reduced to...

`KMnO_(4)` in basic medium is reduced to

A

`K_(2)MnO`

B

`Mn(OH)_(2)`

C

`MnO_(2)`

D

`Mn^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
C
`KMnO_(4)` is first reduced to manganate and then to insoluble manganese dioxide. Colour changes first from purple to green and finally becomes colourless.
`2KMnO_(7) + 2 KOH rarr 2K_(2) MnO_(4) + H_(2) O + O`
`2KMnO+(4) + 2 H_(2) O rarr 2 MnO_(4) + 4KOH + 2O`
`2KMnO_(2) + H_(2)O overset(a l k a l i n e)rarr 2MnO_(2) + 2KOH + 3 [O]`
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Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.

The molarity (m) of KMnO_(4) in the acidic medium is (densityh of KMnO_(4) solution =1.58gmL^(-1)Mw(KMnO_(4))=158gmol^(-1))

Knowledge Check

  • KMnO_(4) in basic medium is used as

    A
    strong oxidising agent
    B
    strong reducing agent
    C
    strong hydrogenating agent
    D
    poor reducing agent

  • 15 g of KMnO_(4) in acidic medium equal to

    A
    0.095 moles
    B
    0.477g equivalents
    C
    9.54 L of 0.05 N `KMnO_(4)`
    D
    10 ml of 0.05 M `KMnO_(4)`

  • For KMnO_(4) in strong basic medium correct combination is -

    A
    (I) (ii) (R)
    B
    (II) (ii) (P)
    C
    (II) (iii) (S)
    D
    (I) (iv) (Q)

    • Similar Questions

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    KMnO_(4) reacts with Kl, in basic medium to form l_(2) and MnO_(2) . When 250 mL of 0.1 M Kl solution is mtextxed with 250 mL of 0.02 M KMnO_(4) in basic medium, what is the number of moles of l_(2) formed?

    KMnO_(4) reacts with KI in basic medium to form I_(2) and MnO_(2) . When 250 mL of 0.1 M KI solution is mixed with 250 ml of 0.02M KMnO_(4) in basic medium, what is the number of moles I_(2) formed ?

    KMnO_(4) reacts with KI in basic medium to from I_(2) and MnO_(2) . When 250 mL of 0.1 M KI solution is mixed with 250 mL of 0.02 M KMnO_(4) in basic medium, what is the number of moles I_(2) formed ?

    100mL of H_2O_2 is oxidised by 100mL of 0.01M KMnO_4 in acidic medium (MnO_4^(ɵ) reduced to Mn^(2+) ). 100mL of the same H_2O_2 is oxidised by VmL of 0.01M KMnO_4 in basic medium. Hence V is

    Molecular weight of KMnO_(4) in acidic medium and neutral medium will be respecitvely -

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