`KMnO_(4)` is first reduced to manganate and then to insoluble manganese dioxide. Colour changes first from purple to green and finally becomes colourless. `2KMnO_(7) + 2 KOH rarr 2K_(2) MnO_(4) + H_(2) O + O` `2KMnO+(4) + 2 H_(2) O rarr 2 MnO_(4) + 4KOH + 2O` `2KMnO_(2) + H_(2)O overset(a l k a l i n e)rarr 2MnO_(2) + 2KOH + 3 [O]`
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KMnO_(4) in basic medium is used as
Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.
The molarity (m) of KMnO_(4) in the acidic medium is (densityh of KMnO_(4) solution =1.58gmL^(-1)Mw(KMnO_(4))=158gmol^(-1))
KMnO_(4) reacts with KI in basic medium to from I_(2) and MnO_(2) . When 250 mL of 0.1 M KI solution is mixed with 250 mL of 0.02 M KMnO_(4) in basic medium, what is the number of moles I_(2) formed ?
100mL of H_2O_2 is oxidised by 100mL of 0.01M KMnO_4 in acidic medium (MnO_4^(ɵ) reduced to Mn^(2+) ). 100mL of the same H_2O_2 is oxidised by VmL of 0.01M KMnO_4 in basic medium. Hence V is
Molecular weight of KMnO_(4) in acidic medium and neutral medium will be respecitvely -
Knowledge Check
KMnO_(4) in basic medium is used as
A
strong oxidising agent
B
strong reducing agent
C
strong hydrogenating agent
D
poor reducing agent
15 g of KMnO_(4) in acidic medium equal to
A
0.095 moles
B
0.477g equivalents
C
9.54 L of 0.05 N `KMnO_(4)`
D
10 ml of 0.05 M `KMnO_(4)`
For KMnO_(4) in strong basic medium correct combination is -
A
(I) (ii) (R)
B
(II) (ii) (P)
C
(II) (iii) (S)
D
(I) (iv) (Q)
A2Z-THE D AND F BLOCK ELEMENTS-KMnO_4 And K_2Cr_2O_46