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In alkaline medium , KMnO(4) reacts as f...

In alkaline medium , `KMnO_(4)` reacts as follows
`2KMnO_(4)+2KOH rarr 2K_(2)MnO_(4)+H_(2)O+O`
Therefore, the equivalent mass of `KMnO_(4)` will be

A

31.5

B

52.7

C

72

D

158

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • In alkaline conditions, KMnO_(4) reacts as follows, 2KMnO_(4) + 2KOH to 2K_(2)MnO_(4)+H_(2)O + [O] Therefore, its equivalent mass will be :

    A
    31.6
    B
    52.7
    C
    72
    D
    `158.0`

  • In permanganate titrations, potassium pemanganats is used an an oxidizing agent in acidic medium. The medium is maintained acidic by the use of dilute sulphuric acid. Potassium permanganate acts as self indicator . The potential equation, when potassium permanganate acts as an oxidizing agent is 2KMnO_(4) + 3H_(2)SO_(4) to K_(2)SO_(4) + 2MnSO_(4) + 3H_(2)O + 5[O] or MnO_(4)^(-) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O Before the end point, the solution remains colourless but after teh equivalence point only one extra drop of KMnO_(4) solution imparts pink colour , i.e. appearance of pink colour indicates end point. These titrations are used for estimation of ferrous salts, oxalic acid, oxalates, hydrogen peroxide, As_(2)O_(3) etc. In alkaline condition, KMnO_(4) reacts as follows : 2KMnO_(4) + 2KOH to 2K_(2)MnO_(4) + H_(2)O + [O] Therefore , its equivalent mass will be

    A
    `31.6`
    B
    `52.7`
    C
    `72.0`
    D
    `158.0`

  • In alkaline condition KMnO_(4) reacts as follows : 2KMnO_(4)+2KOH to 2K_(2)MnO_(2) +H_(2)O +O the eq.wt of KMnO_(4) is

    A
    `52.7`
    B
    158
    C
    `31.6`
    D
    79

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    KMnO_(4) (m.w.=158) oxidises oxalic acid in acid medium to CO_(2) and water as follows : 5C_(2)O_(4)^(2-)+2MnO_(4)^(-)+16H^(+) to 10 CO_(2)+2Mn^(2+)+8H_(2)O What is the equivalent weigth of KMnO_(4) ?

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