Which among the following will be named as dibromidobis-(ethylenediamine) chromium (III) bromide?

Options

A. (a) `[Cr(en)_3]Br_3`
B. (b) `[Cr(en)_2Br_2]Br`
C. (c) `[Cr(en)Br_4]^(-)`
D. (d) `[Cr(en)Br_2]Br`

Answer

B

Explanation

Two Br, two (en) and one Cr are parts of complex. Charge on the complex is
`{:(2(Br),=,-2,,),(2(en),=,0,,), (1(Cr),=,+3,,):}}=+1`
Thus, complex ion is `[Cr(en)_2Br_2]^(+)`.
Since, anion is bromide thus, complex is `[Cr(en)_2Br_2]Br`.