Home
Class 12
CHEMISTRY
Considering H2O as a weak field ligand, ...

Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)

A

(a) `3`

B

(b) `2`

C

(c) `5`

D

(d) `4`

Text Solution

Verified by Experts

The correct Answer is:
C

`._(25)Mn: 3d^5, 4s^2`
`Mn^(2+): 3d^5`, i.e., 5 unpaired electrons because `H_2O` is weak field ligand and does not force to pairing.
Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    A2Z|Exercise Metal Carbonyls, Stability Of Complexes And Applications|23 Videos
  • COORDINATION COMPOUNDS

    A2Z|Exercise Section B - Assertion Reasoning|15 Videos
  • COORDINATION COMPOUNDS

    A2Z|Exercise Wemer Theory And Vbt|42 Videos
  • CHEMICAL KINETICS

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • ELECTROCHEMISTRY

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

The number of unpaired electron(s) in [Fe(H_2O)_6]^(2+) is

Number of unpaired electrons in [Mn(CN)_(6)]^(3-) is

Number of unpaired electrons in Mn^(3+) is

Number of unpaired electrons in Mn^(4+) is

Total number of unpaired electrons in O_2^(2-)

The number of unpaired electron in Mn^(4+) (Z = 25) is :-

Number of unpaired electrons present in [Ni(H_(2)O)_(6)]^(2+)