The major product obtained on treatment of `CH_(3) CH_(2)CH(F)`
`CH_(3)with CH_(3)O^(-)//CH_(3)OH` is .

Options

A. `CH_(3)CH_(2)CH(OCH_(3))CH_(3)`
B. `CH_(3)CH=CHCH_(3)`
C. `CH_(3)CH_(2)CH=CH_(2)`
D. `CH_(3)CH_(2)CH_(2)CH_(2)OCH_(3)`

Explanation

To determine the major product obtained from the reaction of `CH3CH2CHFCH3` with `CH3O^-/CH3OH`, we can follow these steps:

### Step 1: Identify the Reactants
The reactants are:
- `CH3CH2CHFCH3` (2-fluorobutane)
- `CH3O^-` (methoxide ion) in `CH3OH` (methanol)

### Step 2: Understand the Reaction Mechanism
The reaction involves an elimination process, specifically an E2 elimination, where the methoxide ion acts as a base. This will lead to the formation of alkenes by removing a hydrogen atom and the fluorine atom from adjacent carbon atoms.

### Step 3: Identify Possible Elimination Sites
In `CH3CH2CHFCH3`, we can identify the hydrogen atoms that can be eliminated along with the fluorine atom:
1. Elimination between the second carbon (C2) and the first carbon (C1) leads to:
- Product: `CH3CH=CHCH3` (but-2-ene)
2. Elimination between the second carbon (C2) and the third carbon (C3) leads to:
- Product: `CH3CH2CH=CH2` (but-1-ene)

### Step 4: Determine Substitution of Alkenes
Now, we need to evaluate the substitution of the alkenes formed:
- `CH3CH=CHCH3` (but-2-ene) is a more substituted alkene (it has two alkyl groups attached to the double bond).
- `CH3CH2CH=CH2` (but-1-ene) is less substituted (it has only one alkyl group attached to the double bond).

### Step 5: Apply Zaitsev's Rule
According to Zaitsev's rule, the more substituted alkene is favored as the major product. Therefore, the major product of this reaction will be:
- **Major Product:** `CH3CH=CHCH3` (but-2-ene)

### Final Answer
The major product obtained on treatment of `CH3CH2CHFCH3` with `CH3O^-/CH3OH` is `but-2-ene` (CH3CH=CHCH3).

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