Aqueous solution of two compounds `M_(1) - O - H and M_(2) - O - H` are prepared in two different beakers . If electronegativity of `M_(1) = 3.4, M_(2) = 1.2, 0 = 3.5 and H = 2.1`, then the nature of two solution will be respectively

Options

A. Acidic, basic
B. acidic acidic
C. basic, acidic
D. basic, basic

Explanation

To determine the nature of the two aqueous solutions of the compounds \( M_1OH \) and \( M_2OH \), we will analyze the electronegativity values provided and assess the type of bond present in each compound.

### Step-by-Step Solution:

1. **Identify the Electronegativity Values**:
- For \( M_1 \): Electronegativity = 3.4
- For \( M_2 \): Electronegativity = 1.2
- For Oxygen (O): Electronegativity = 3.5
- For Hydrogen (H): Electronegativity = 2.1

2. **Calculate the Electronegativity Difference for \( M_1OH \)**:
- Difference between \( M_1 \) and \( O \):
\[ |3.4 - 3.5| = 0.1 \]
- This small difference indicates a covalent bond.

3. **Analyze the Bond in \( M_1OH \)**:
- The bond between \( O \) and \( H \):
\[ |3.5 - 2.1| = 1.4 \]
- This difference indicates a significant ionic character in the \( O-H \) bond.

4. **Determine the Nature of \( M_1OH \)**:
- Since the \( O-H \) bond has more ionic character and \( M_1 \) has a covalent bond with \( O \), the solution will release \( H^+ \) ions, making it acidic.

5. **Calculate the Electronegativity Difference for \( M_2OH \)**:
- Difference between \( M_2 \) and \( O \):
\[ |1.2 - 3.5| = 2.3 \]
- This large difference indicates a strong ionic bond.

6. **Analyze the Bond in \( M_2OH \)**:
- The bond between \( O \) and \( H \) remains the same:
\[ |3.5 - 2.1| = 1.4 \]
- Again, this bond has ionic character.

7. **Determine the Nature of \( M_2OH \)**:
- Since the bond between \( M_2 \) and \( O \) is highly ionic, the solution will release \( OH^- \) ions, making it basic.

### Conclusion:
- The nature of the two solutions is:
- \( M_1OH \): Acidic
- \( M_2OH \): Basic

### Final Answer:
The nature of the two solutions will be respectively **acidic** for \( M_1OH \) and **basic** for \( M_2OH \).

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