The electronegativity difference between two atoms A and B is `2`, then percentage of covalent character in the molecule is

Options

A. `54% `
B. `40% `
C. `23% `
D. `72% `

Explanation

To find the percentage of covalent character in a molecule when given the electronegativity difference between two atoms A and B, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electronegativity Difference**:
We are given that the electronegativity difference (ΔX) between atoms A and B is 2.

2. **Use the Formula for Percentage Ionic Character**:
The formula to calculate the percentage of ionic character is:
\[ \text{Percentage Ionic Character} = 16 \times \Delta X + 3.5 \times (\Delta X)^2 \]
Here, ΔX = 2.

3. **Substitute the Value of ΔX into the Formula**:
Plugging in the value of ΔX:
\[ \text{Percentage Ionic Character} = 16 \times 2 + 3.5 \times (2)^2 \]

4. **Calculate Each Term**:
- First term: \( 16 \times 2 = 32 \)
- Second term: \( 3.5 \times (2)^2 = 3.5 \times 4 = 14 \)

5. **Add the Two Terms Together**:
\[ \text{Percentage Ionic Character} = 32 + 14 = 46 \]

6. **Calculate the Percentage Covalent Character**:
The percentage of covalent character can be found by subtracting the percentage ionic character from 100:
\[ \text{Percentage Covalent Character} = 100 - \text{Percentage Ionic Character} = 100 - 46 = 54 \]

7. **Final Answer**:
Therefore, the percentage of covalent character in the molecule is **54%**.