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The electronegativity of H and CI are 2....

The electronegativity of `H` and CI are 2.1 and 3.0 respectively. The correct statement `(s)` about the nature of `HCI` is/are:

A

`17%` ionic

B

`83%` ionic

C

`50%` ionic

D

`100%` ionic

Text Solution

Verified by Experts

The correct Answer is:
a
`%` ionic character `= 16(X_(A) - X_(B))+ 3.5 (X_(A) - X_(B))^(2)`
`16(3.0 - 2.1) + 3.5(3.0 - 2.1)^(2)`
`= 14.4 + 2.835 = 17.235 ~~ 17%`
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