The dipole moment of `HBr` is ` 1.6 xx 10^(-30) cm` and interatomic spacing is `1 Å`. The `%` ionic character of `HBr` is

Options

A. 7
B. 10
C. 15
D. 27

Explanation

To calculate the percentage ionic character of HBr, we will use the formula:

\[ \text{Percentage Ionic Character} = \left( \frac{\text{Dipole Moment}}{\text{Interatomic Spacing} \times \text{Charge on Electron}} \right) \times 100 \]

### Step 1: Identify the given values
- Dipole moment of HBr = \(1.6 \times 10^{-30} \, \text{cm}\)
- Interatomic spacing = \(1 \, \text{Å} = 1 \times 10^{-10} \, \text{m}\)
- Charge on an electron = \(1.6 \times 10^{-19} \, \text{C}\)

### Step 2: Convert dipole moment to meters
Since the dipole moment is given in centimeters, we need to convert it to meters:
\[ 1.6 \times 10^{-30} \, \text{cm} = 1.6 \times 10^{-30} \times 10^{-2} \, \text{m} = 1.6 \times 10^{-32} \, \text{m} \]

### Step 3: Substitute the values into the formula
Now we can substitute the values into the percentage ionic character formula:
\[ \text{Percentage Ionic Character} = \left( \frac{1.6 \times 10^{-32} \, \text{m}}{(1 \times 10^{-10} \, \text{m}) \times (1.6 \times 10^{-19} \, \text{C})} \right) \times 100 \]

### Step 4: Calculate the denominator
Calculate the denominator:
\[ 1 \times 10^{-10} \, \text{m} \times 1.6 \times 10^{-19} \, \text{C} = 1.6 \times 10^{-29} \, \text{m} \cdot \text{C} \]

### Step 5: Calculate the percentage ionic character
Now substitute the denominator back into the formula:
\[ \text{Percentage Ionic Character} = \left( \frac{1.6 \times 10^{-32}}{1.6 \times 10^{-29}} \right) \times 100 \]

### Step 6: Simplify the fraction
\[ \frac{1.6 \times 10^{-32}}{1.6 \times 10^{-29}} = 10^{-3} \]

### Step 7: Multiply by 100
\[ \text{Percentage Ionic Character} = 10^{-3} \times 100 = 0.1 \times 100 = 10\% \]

### Final Answer
The percentage ionic character of HBr is **10%**.

---