Home
Class 11
CHEMISTRY
A: tetracynomethance, B: Carbon dioxide ...

A: tetracynomethance, B: Carbon dioxide , C: Benzene, D: `1, 3`butadiene
Ratio of `s and p` bond is in order

A

`A = B lt C lt D`

B

`A = B lt D lt C`

C

`A = B = C = D`

D

`C lt D lt A lt B`

Text Solution

Verified by Experts

The correct Answer is:
a

(a) Tetracyanomethane

(b) `O = C = O (sigma)/(pi) = (2)/(2) = 1`
(c)
(d)
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    A2Z|Exercise Vsepr Theory And Hybridisation|46 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    A2Z|Exercise Molecular Orbitial Theory|42 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    A2Z|Exercise Dipole Moment|28 Videos
  • ATOMIC STRUCTURE

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • CHEMICAL EQUILIBRIUM

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

For compounds , A : Tetracuanoethern B : Carbon dioxide C: Benzene D : 1 , 3-Butaidene . Ratio of sigma and pi bonds is in order :

A:tetracyanomethane B:carbondioxide C:Benzene C:1,3-But-di-ene Ratio of sigma and pi bonds is in order:

The C-C bond order in benzene is :

The carbon-carbon bond order in benzene is

Carbon-carbon bond-order in benzene is -1.5 due to

Consider the following compounds A. Chloroethene B. Benzene C. 1,3-butadiene D. 1,3,5-hexatriene All the carbon atoms are sp^(2) hybridised in

Assertion : The central carbon - carbon bond in 1, 3- butadiene is shorter than n -butane. Reason : In butadiene the central bond has sp^(2)-sp^(2) nature whereas in butane it is sp^(3)-sp^(3) .

Consider the following compounds (i) Chloroethane (ii) Benzene (iii) 1,3-butadiene (iv) 1,3,5-hexatriene All the carbon atoms are sp^(2) hybridized in