निम्नलिखित के मान ज्ञात कीजिए -
(i) ` tan. (19 pi)/3 ` (ii) ` sec ((-22pi)/3)`

Explanation

(i) ` tan. (19pi)/3 = tan ((19 xx 180^(@))/3 ) `
` = tan (1140^(@))`
` = tan ( 3 xx 360^(@) + 60^(@))`
` = tan 60^(@) = sqrt(3)`
(ii) ` sec ((-22pi)/3 ) = sec ((22pi)/3 )`
` = sec ( (22xx 180^(@))/3 ) = sec 1320^(@)`
` = sec ( 3 xx 360^(@) + 240^(@) ) = sec 240^(@)`
` = sec ( 180^(@) + 60^(@) )= - sec 60^(@)`
` = -2`