समीकरण ` 4 cos^(2) theta + sqrt(3) = 2 (sqrt(3)+1) cos theta` को हल कीजिए ।

Explanation

` 4 cos^(2) theta + sqrt(3) = 2 (sqrt(3)+1) cos theta ) `
` rArr 4 cos^(2) theta + sqrt(3) = 2 sqrt(3) cos theta + 2 cos theta `
` rArr 4 cos^(2) theta - 2 cos theta - 2 sqrt(3) cos theta + sqrt(3) = 0 `
` rArr 2 cos theta (2 cos theta - 1) - sqrt(3) (2 cos theta -1) = 0 `
` rArr ( 2 cos theta - 1) (2 cos theta - sqrt(3))=0`
` rArr 2 cos theta - 1 = 0 "या " 2 cos theta - sqrt(3) = 0 `
अब ` 2 cos theta - 1 = 0 `
` rArr cos theta = 1/2 = cos .pi/3 `
` rArr cos theta = (sqrt(3))/2 = cos . pi/6 `
` rArr theta = 2npi pm pi/6 .`