हल कीजिए - ` sec theta - 1 = ( sqrt( 2) -1) tan theta `

Explanation

` sec theta - 1 = (sqrt(2)-1)tan theta `
` rArr ( sec theta - 1)^(2) = (sqrt(2)-1)^(2) * tan ^(2)theta `
` = (2+1-2sqrt(2))(sec^(2)theta-1)`
` = ( 3 - 2 sqrt(2)) (sec^(2) theta-1)`
` (sec theta-1)^(2) = (3-2sqrt(2)) (sec theta-1)(sec theta +1)`
` rArr ( 3- 2sqrt(2)) (sec theta-1)(sec theta+1) - (sec theta-1)^(2) = 0 `
` rArr (sec theta - 1) [(3 -2sqrt(2))(sec theta+1) - (sec theta -1)] = 0 `
` rArr (sec theta - 1) [ (2 - 2sqrt(2))sec theta + (4 - 2sqrt(2))]=0`
` rArr (sec theta - 1) [ (2 - 2sqrt(2)) sec theta - sqrt(2) (-2 sqrt(2) +2)] =0`
` rArr (sec theta -1) (2 - 2sqrt(2))(sec theta - sqrt(2))=0`
` rArr sec theta =1 `
` rArr cos theta = 1 `
` rArr theta = 2 n pi pm 0 = 2npi`