समीकरण ` sin 3 theta = sin 2 theta ` को हल कीजिए ।

Explanation

` sin 3 theta = sin 2 theta `
` rArr 3 theta = n pi = (-1)^(n).2theta `
यदि ` n = 2K` तो,
` 3 theta = 2 k pi +(-1)^(2k)* 2theta`
` = 2kpi + 2 theta " " [ :' (-1)^(2k) = 1 ] `
` rArr theta = 2 kpi`
यदि` n = 2k +1,` तो ,
` 3 theta = ( 2k +1) pi +(-1)^(2k+1)*2theta`
` = ( 2k+1) pi- 2 theta [ :' (-1)^(2k+1) = -1] `
` rArr 5 theta = (2k +1) pi`
` rArr theta = ( 2k+1) pi/5`