` sin p theta = cos q theta ` से ` theta ` का व्यापक मान ज्ञात कीजिए ।

Explanation

` sin p theta = cos q theta`
` rArr cos q theta = sin p theta`
` = cos (pi/2 - ptheta )`
` rArr q theta = 2npi pm (pi/2 - ptheta)`
अब ` q theta = 2npi+(pi/2-ptheta)`
` rArr (p+q) theta = 2npi + pi/2 =(4n+1) pi/2`
` rArr theta = ((4n+1)pi)/(2(p+q))`
अब ` q theta = 2npi - (pi/2-ptheta)`
` rArr (q-p) theta = 2npi -pi/2 = (4n-1)pi/2 `
` rArr theta = ((4n-1)pi)/(2(q-p))`