`(1/(1-4i)-2/(1+i))((3-4i)/(5+i))` को मानक रूप में परिवर्तित कीजिए।

Explanation

दिया है : `(1/(1-4i) -2/(1+i))((3-4i)/(5+i))`
`=[(1(1+i)-2(1-4i))/((1-4i)(1+i))]((3-4i)/(5+i))`
`=(1+i-2+8i)/(1+i-4i-4i^(2))xx(3-4i)/(5+i)`
`=(-1+9i)/(1-3i-4xx(-1))xx(3-4i)/(5+i)`
`=(-1+9i)/(5-3i)xx(3-4i)/(5+i)`
`=(-3+4i+27i-36i^(2))/(25-10i-3xx(-1))=(33+31i)/(28-10i)`
`=((33+31i))/((28-10i))xx((28+10i))/((28-10i))xx((28+10i))/((28+10i))`
`=(24+330i+868i+310i^(2))/(784-100i^(2))`
`=(924+1198i+310xx(-1))/(784-100xx(-1))" "( :' i^(2)=-1)`
`=(614+1198i)/(884)`
`=(2(307+599i))/(2xx442)`
`=(307+599i)/442=307/442+599/442 i`