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In Young's double slit experiment angula...

In Young's double slit experiment angular width of a fringe formed on a distant screen is `0.1^(@)` . The wavelength of the light used in the experiment is 6000 Å. What is the distance between the two slits ?

Text Solution

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We know angular width of a fringe ,
`theta =(lambda)/(2d)`
` :. " " 2d =(lambda)/(theta) = (6000xx10^(-10))/(pi/(180)xx0.1)=(6000xx180xx10^(-10))/(22/(7)xx0.1)`
=`3.44 xx 10^(-3)` m
`:.` Distance between the slits =`3.44 xx 10^(-4)` m.
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