In Young' s experiment, the path difference between two interfering waves at a point on the screen is 167.5 times the wavelength of the monochromatic light used. Is the point or bright? If the path difference is 0.101 mm , find the wavelength of light used.

In Young's double slit experiment what is the path difference between the two light waves forming 5th bright band on the screen ?

In Young's double slit experiment the distance between the two slits is d and wavelength of the light used is lambda . The angular width of the fringe

In Young's double slit experiment the intensity of light on the screen where the where the path difference is lambda is k ( lambda being the wavelength of light used). The intensity at a point where the path difference is (lambda)/(4) will be

In Young's double slit experiment the distance of the screen from the plane of the slits is 1.0 m. The wavelength of light used and width of the fringe are 6000 Å and 2 mm respectively. If the wavelength of the light used is 4800 Å, the width of the fringe will be

In Young's double slit experiment angular width of a fringe formed on a distant screen is 0.1^(@) . The wavelength of the light used in the experiment is 6000 Å. What is the distance between the two slits ?

The wavelength of a travelling wave is 2 m. What is the phase difference between two particles 1 m apart.in the path of the wave.

In Young’s double slit experiment the distance between two slits is 0.3 xx 10^-3 m, the distance betwe'en slits and screen is 1.2 m. Distance of second bright fringe from the centre of the central bright fringe is 4.5 xx 10^-3 m. Obtain wavelength of the ligth .

The potential difference between two points in an electric field does not depend on the path connecting them. Explain.