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Maximum intensity in Young's double slit...

Maximum intensity in Young's double slit experiment is `I_(0)` . If one slit is closed the intensity would be

A

`I_(0)`

B

`I_(0)/(4)`

C

`I_(0)/(3)`

D

`I_(0)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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The intensity at the central maxima in Young' s double slit experiment is I_(0) . Find out the intensity at a point where the path difference is (lambda)/(6) , (lambda)/(4) and (lambda)/(3) .

The intensity at the maximum in a Young's double slit experiment is I_(0) . Separation between two slits is d = 5lambda , where lambda is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance D = 10 d?

Knowledge Check

  • If young' s double slit experiment is performed using white light, then

    A
    the central fringe will be white
    B
    no fringe will be completely dark
    C
    the fringe adjacent to the central one will be red
    D
    the fringe adjacent to the central one will be violet
  • If the ratio of maximum and minimum intensities of the interference fringes obtained in Young's double slit experiment is 4: 1 then the ratio of the amplitudes of the two coherent sources will be

    A
    `4:1`
    B
    `3:1`
    C
    `2:1`
    D
    `1:1`
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