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Po^210 has half-life of 140 d. In 1g Po^...

`Po^210` has half-life of 140 d. In 1g `Po^210` how many disintegration will take place every second ? [Avogadro's number = `6.023xx10^23`]

Text Solution

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Disintegration constant, `lambda=0.693/T = 0.693/(140xx24xx60xx60)s^(-1)`
Number of atoms in 210 g `Po^210` = Avogadro's number = `6.023xx10^23`
`therefore` Number of atoms in 1 g `Po^210 , N=(6.023xx10^23)/210`
`therefore` Disintegration per second = activity =`lambdaN`
`=0.693/(140xx24xx60xx60)xx(6.023xx10^23)/210`
`=1.64xx10^14` dps
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