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When .4Be^9 is hit by alpha-particles a ...

When `._4Be^9` is hit by `alpha`-particles a neutron is emitted resulting in the formation of a new element. Identify the element and write the complete reaction equation.

Text Solution

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`alpha`-particle: `._2He^4` , neutron:`._0n^1`
`therefore` Let the new element be `._ZX^A` .
From the laws of conservation of mass number and atomic number,
9 + 4 =A + 1 or, A=12
and 4 +2 =Z+0 or, Z=6
`therefore` The new element =`._6C^12` (carbon)
`therefore` The complete equation of the reaction : `._4Be^9 + ._2He^4 to ._6C^12 + ._0n^1`
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