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The half-life of .38^90Sr is 28 years . ...

The half-life of `._38^90Sr` is 28 years . What is the disintegration rate of 15 mg of this isotope ?

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Number of atoms in 15 mg of `._38^90Sr = (6.023xx10^23xx15xx10^(-3))/90`
Disintegration constant, `lambda=0.693/T=0.693/(28xx365xx24xx60xx60)s^(-1)`
`therefore` Rate of disintegration,
`(dN)/(dt)=lambdaN`
`=0.693/(28xx365xx24xx60xx60)xx(6.023xx10^23xx15xx10^(-3))/90`
`=7.87xx10^10` Bq
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