An n-p-n transistor is Kept in common- emitter con- figuation. AmpIification factor of the transistor is 100.If the coIIector current is changed by 1 mA, what wiII by the corresponding change in the emitter current?

Explanation

Amplification factor ,`beta=(DeltaI_(C))/(DeltaI_(B))`
`:." "DeltaI_(B)=(DeltaI_(C))/(beta)=(1)/(100)=0.01`mA
So, change in emitter current ,
`DeltaI_(E)=DeltaI_(C)+DeltaI_(B)=1+0.01=1.01`mA