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Derive the relationship between open loo...

Derive the relationship between open loop gain and closed loop gain of an amplifier circuit with reference to feedback ratio.

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What is the product of open loop gain and feedback ratio of the amplifier in a feedback oscillator.

Statement I : The frequency of the output signal from a feedback oscillator depends on its feedback ratio. Statement II : A feedback oscillator circuit is made in such a way that the closed loop gain of the amplifier reaches to an infinite value.

A n-p-n transistor is connected to common emitter configuration in a given amplifier. A load resistance of 800 Omega is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 Omega the voltage gain and the power gain of the amplifier will respectively be

Open loop gain of an amplifier is A. If a feedback oscillator is made by this amplifier then what feedback ratio is to be taken?

A metal rod PQ is resting on the rails A'B' and positioned between the poles of a permanent magnet. The rails, the rod and the magnetic field are in three mutually perpendicular directions. A galvanometer G connects the rails through a switch K. Length of the rod = 15 cm, B = 0.50 T, resistance of the closed loop containing the rod = 9.0 mOmega . Assume the field to be uniform. Is there an excess charge built up at the ends of the rods when K is open? What if K is closed?

A metal rod PQ is resting on the rails A'B' and positioned between the poles of a permanent magnet. The rails, the rod and the magnetic field are in three mutually perpendicular directions. A galvanometer G connects the rails through a switch K. Length of the rod = 15 cm, B = 0.50 T, resistance of the closed loop containing the rod = 9.0 mOmega . Assume the field to be uniform. Suppose K is open and the rod is moved with a speed of 12 cm. s^(-1) in the direction shown. Give the polarity and magnitude of the induced emf.

A metal rod PQ is resting on the rails A'B' and positioned between the poles of a permanent magnet. The rails, the rod and the magnetic field are in three mutually perpendicular directions. A galvanometer G connects the rails through a switch K. Length of the rod = 15 cm, B = 0.50 T, resistance of the closed loop containing the rod = 9.0 mOmega . Assume the field to be uniform. How much power is required by an external agent to keep the rod moving at the same speed (=12cm.s^(-1)) when K is closed? How much power is required when K is open?

The figure shows two identical parallel plate capacitor connected to a battery with the switch S closed. The switch is now opened and the free space between the plates of the capacitor is filled with a dielectric of dielectric constant 3. Find the ratio of the total electrostatic energy stored in both capacitors before and after the introduction of the dielectric.

A metal rod PQ is resting on the rails A'B' and positioned between the poles of a permanent magnet. The rails, the rod and the magnetic field are in three mutually perpendicular directions. A galvanometer G connects the rails through a switch K. Length of the rod = 15 cm, B = 0.50 T, resistance of the closed loop containing the rod = 9.0 mOmega . Assume the field to be uniform. With K open and the rod moving uniformly, there is no net force on the electrons in thr rod PQ even though they do experience magnetic force due to the motion of the rod. Explain.

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