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The number of silicon atoms per m^(3) is...

The number of silicon atoms per `m^(3)` is `5xx10^(28)`. This is doped simultaneously with `5xx10^(22)` atoms per `m^(3)` of arsenic and `5xx10^(20)` atoms per `m^(3)` of indium. Calculate the number of electrons and holes . Given that `n_(i)=1.5 xx10^(16) "m"^(-3)`. Is the material n-type or p-type?

Text Solution

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The number density of free electrons,
`n_(e)=5xx10^(22)-5xx10^(20)=4.95xx10^(22) "m"^(-3)`
Number density of hole
`n_(h)=(n_(i)^(2))/(n_(e))=(1.5xx10^(16))^(2)/(4.95xx10^(22))=4.55xx10^(9)"m"^(-3)`
`because n_(e)gtn_(h)` the material is of n-type.
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