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Find maximum and minimum values of `(x^2-x+1)/(x^2+x+1)` using Calculus.

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The correct Answer is:
`y_(max)=(1+1+1)/(1-1+1)=3` and `y_(min)=(1-1+1)/(1+1+1)=(1)/(3)`
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CHHAYA PUBLICATION-QUESTIONS PAPER -2019-WBJEE 2019
  1. Find maximum and minimum values of (x^2-x+1)/(x^2+x+1) using Calculus.

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  7. If int2^(2^x)*2^xdx=A*2^(2^x)+c, then A=

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  10. The general solution of the differential equation (1+e^((x)/(y)))dx+(1...

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  11. General solution of (x+y)^2(dy)/(dx)=a^2,ane0 is

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  18. Let: RtoR be defined by f(x)=x^2-(x^2)/(1+x^2) for all x inR. Then

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