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The equation of the plane through (1,2,-...

The equation of the plane through (1,2,-3) and (2,-2,1) and parallel to x axis is

A

`y-z+1=0`

B

`y-z-1=0`

C

`y+z-1=0`

D

`y+z+1=0`

Text Solution

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The correct Answer is:
D
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Find the equation of the plane through the points (2, 3, 1) and (4, -5, 3) and parallel to the x-axis.

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Knowledge Check

  • The equation of the plane passing through the point (2, -3, 5) and parallel to zx-plane is -

    A
    `z+x=7`
    B
    `z-5=0`
    C
    `x-2=0`
    D
    `y+3=0`

  • The equation of the line passing through the point (2, -3, 1) and parallel to the line (3x-2)/(3)=(2y+1)/(4)=(3-z)/(2) is -

    A
    `(x-2)/(3)=(y+3)/(4)=(z-1)/(-2)`
    B
    `(x-2)/(1)=(y+3)/(2)=(z-1)/(2)`
    C
    `(x+2)/(1)=(y-3)/(2)=(z+1)/(-2)`
    D
    `(x-2)/(1)=(y+3)/(2)=(z-1)/(-2)`

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    Find the equation of the plane through the point (3,2,2),(1,0,-1) and parallel to the line (x-1)/(1)=(y-1)/(-2)=(z-2)/(3) . Convert to vector from.

    Show that the equation of the plane passing through the point (1,2,3) and parallel to the plane 3x+4y-5z=3 is given by 3x+4y-5z=-4 .

    Show that the equation of the plane passing through the point (1,2,3) and parallel to the plane. 3x + 4y - 5z = 3 is given by 3x + 4y - 5z = -4.

    Find the equation of the plane passing through the point (4,1,1) and parallel to 3x-4y+7z+5 =0

    Find the vector equation of the line passing through the point (2,-3,1) and parallel to the planes vec r.(2hati-3hatj-hatk)=3 and vec r.(hati+hatj-hatk)=4 .

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