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(1+y^(2))(1+logx)dx+xdy=0, given y=1, wh...

`(1+y^(2))(1+logx)dx+xdy=0`, given y=1, when x=1

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The correct Answer is:
`tan^(-1)y+log|x|+((1)/(2))(logx)^(2)=(pi)/(4)`
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