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cosylog(secx+tanx)dx=cosxlog(secy+tany)d...

`cosylog(secx+tanx)dx=cosxlog(secy+tany)dy`

Text Solution

Verified by Experts

The correct Answer is:
`[log|secx+tanx|]^(2)-[log|secy+tan|]^(2)=c`
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