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(1+e^(2x))dy+e^(x)(1+y^(2))dx=0 it being...

`(1+e^(2x))dy+e^(x)(1+y^(2))dx=0` it being given that y=1 when x=0

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The correct Answer is:
`tan^(-1)(e^(x))+tan^(-1)y=(pi)/(2)`
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