Home
Class 12
MATHS
Consider the equation az+b bar(z)+c=0" "...

Consider the equation `az+b bar(z)+c=0" ""where" " "a,b,cin Z`
If `|a|=|b| and bar(ac)!=bar(bc),` then z has

A

infinite solutions

B

no solutions

C

finite solutions

D

cannot say anything

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • COMPLEX NUMBER

    CHHAYA PUBLICATION|Exercise SAMPLE QUESTION FOR COMPETITIVEEXAMS(Multiple Corrrect Answer type)|7 Videos
  • CIRCLE

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams (E. Assertion-Reason Type)|2 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination (Assertion - Reason Type)|2 Videos

Similar Questions

Explore conceptually related problems

Consider the equation az+bar(bz)+c=0" ""where" " "a,b,cin Z If |a|=|b|!=0and bar(a)c=bar(b)c, "then" " " az+b bar(z)+c=0 represents

Consider the equation az+b bar(z)+c=0" ""where" " "a,b,cin Z If |a|!=|b|, then z represents

If bar(z)=-3+5i" "then" z=

Solve the equation z^(2)+|Z|=0 where z is a complex quantity.

Let a ,b and c be any three nonzero complex number. If |z|=1 and' z ' satisfies the equation a z^2+b z+c=0, prove that a .bar a = c .bar c and |a||b|= sqrt(a c( bar b )^2)

Find the slope of bar(AB) , where A(-4, 2), B(-4, -2)

Show that the equation a z^3+b z^2+ barb z+ bara =0 has a root alpha such that |alpha|=1,a ,b ,z and alpha belong to the set of complex numbers.

Given that the complex numbers which satisfy the equation | z bar z ^3|+| bar z z^3|=350 form a rectangle in the Argand plane with the length of its diagonal having an integral number of units, then area of rectangle is 48 sq. units if z_1, z_2, z_3, z_4 are vertices of rectangle, then z_1+z_2+z_3+z_4=0 rectangle is symmetrical about the real axis a r g(z_1-z_3)=pi/4or(3pi)/4

Identify the locus of z if bar z = bar a +(r^2)/(z-a).

(d) answer ANY one question :1. bar a, bar b and bar c be three vectors such that bar a +bar b+ bar c =0 and |bar a|=1, |bar b|=4,|bar c |=2 . Evlautae bar a.bar b + bar b.bar c+bar c.bar a .