Home
Class 12
MATHS
Show that , (2n)! =2^(n).n![1.3.5…(2n-1)...

Show that , `(2n)! =2^(n).n![1.3.5…(2n-1)].`

Promotional Banner

Topper's Solved these Questions

  • PERMUTATION AND COMBINATION

    CHHAYA PUBLICATION|Exercise EXERCISE (7A) (MCQ )|9 Videos

  • PERMUTATION AND COMBINATION

    CHHAYA PUBLICATION|Exercise EXERCISE 7A ( Very Short Answer Type Questions )|25 Videos

  • PARABOLA

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams ( E Assertion -Reason Type )|2 Videos

  • PLANE

    CHHAYA PUBLICATION|Exercise Sample Question for Competitive Examination( E Assertion - Reason Type )|2 Videos

Similar Questions

Explore conceptually related problems

Find the sum of the series .^(n)C_(0)+2.^(n)C_(1)x+3.^(n)C_(2)x^(2)+....+(n+1).^(n)C_(n)x^(n) and hence show that , .^(n)C_(0)+2.^(n)C_(1)x+3.^(n)C_(2)x^(2)+....+(n+1)^(n)C_(n)=(n+2)2^(n-1)

Show that : (^(4n)C_(2n))/(^(2n)C_n) = (1.3.5...(4n-1))/{1.3.5...(2n-1)}^2

For every natural number n, show that 7^(2n)+2^(3n-3)*3^(n-1) is always divisible by 25.

During the n th second of its motion a body covers a distance s_(n) with uniform acceleration a and initial velocity u. Show that a = (2s_(n)-2u)/(2n-1) .

If (1+x)^(n)=C_(0)+C_(1)x+C_(2)x^(2)+...+C_(n)x^(n) "show that ", (1)/(1!(n-1)!)+(1)/(3!(n-3)!)+(1)/(5!(n-5)!)+....=(2^(n-1))/(n!)

Show that (.^(4n)C_(2n))/(.^(2n)C_(n))=(1.3.5......(4n-1))/({1.3.5......(2n-1)}^(2)) .

If A={:[(3,-4),(1,-1)]:}, then by principle of mathematics induction show that, A^(n)={:[(1+2n,-4n),(n,1-2n)]:} for all n in N.

Show : 2^(n)-(n)/(1!).2^(n-1)+(n(n-1))/(2!).2^(n-2)-....+(-1)^(n)=1

If n is a positive integer, show that, (n+1)^(2) + (n+2)^(2) + …+ 4n^(2) = (n)/(6)(2n+1)(7n+1)

If (1+x)^(n)=1+""^(n)C_(1)x+""^(n)C_(2)x^(2)+….+""^(n)C_(n) x^(n) show that, n*2^(n-1)=""^(n)C_(1)+2*""^(n)C_(2)+….. +n*""^(n)C_(n) .