Home
Class 12
MATHS
Find the equation to the circle describe...

Find the equation to the circle described on the common chord of the given circles `x^(2) + y^(2) - 4x - 5 = 0` and `x^(2) + y^(2) + 8x + 7 = 0` as diameter.

Text Solution

Verified by Experts

The correct Answer is:
`x^(2) + y^(2) + 2x + 1 = 0`
Promotional Banner

Topper's Solved these Questions

  • CIRCLE

    CHHAYA PUBLICATION|Exercise Exercise 3 (Multiple Choice Questions)|15 Videos

  • CIRCLE

    CHHAYA PUBLICATION|Exercise Exercise 3 (Very Short Answer Type Questions)|18 Videos

  • CALCULUS

    CHHAYA PUBLICATION|Exercise JEE Advanced Archive (2014)|2 Videos

  • COMPLEX NUMBER

    CHHAYA PUBLICATION|Exercise SAMPLE QUESTION FOR COMPETITIVE EXAMS(Multiple Corrrect Answer type)|11 Videos

Similar Questions

Explore conceptually related problems

Find the equation to the circle described on the common chord of the circles x^(2) + y^(2) - 4x - 2y - 31 = 0 and 2x^(2) + 2y^(2) - 6x + 8y - 35 = 0 as diameter.

Find the equation to the circle described on the common chord of the given circles x^2 + y^2 = 4x + 5 and x^2 + y^2 + 8x + 7 = 0 as diameter.

Find the equation of the circle described on the common chord of the circles x^2+y^2-4x-5=0 and x^2+y^2+8x+7=0 as diameter.

Find the equation to the common chord of the two circles x^(2) + y^(2) - 4x + 6y - 36 = 0 and x^(2) + y^(2) - 5x + 8y - 43 = 0 .

The equation of the circel whose diameter is the common chord of the circles x ^(2) + y^(2) +2x +3y+2=0 and x ^(2) + y^(2) +2x -3y-4=0 is-

Find the equation of the common chord of the two circles x^(2) + y^(2) - 4x - 2y - 31 = 0 and 2x^(2) + 2y^(2) - 6x + 8y - 35 = 0 and show that this chord is perpendicular to the line joining the two centres.

Find the equation of the circle passing through the points of intersection of the circles x^(2) + y^(2) - x + 7y - 3 = 0, x^(2) + y^(2) - 5x - y + 1 = 0 and having its centre on the line x+y = 0.

Find the equation of the common chord of the two circles x^(2)+y^(2)-4x - 10y - 7 = 0 and 2x^(2) + 2y^(2) - 5x + 3y + 2 = 0 . Show that this chord is perpendicular to the line joining the centres of the two circles.

The equation of the circle whose diameter is the common chord of the circles x^2+y^2+3x+2y+1=0 and x^2+y^2+3x+4y+2=0 is

The length of the common chord of the two circles x^2+y^2-4y=0 and x^2+y^2-8x-4y+11=0 is