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Find the equation of the circle passing ...

Find the equation of the circle passing through (6, -5) and having centre at (3, -1).

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The correct Answer is:
`x^(2) + y^(2) - 6x + 2y - 15 = 0`
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CHHAYA PUBLICATION-CIRCLE-Exercise 3 (Very Short Answer Type Questions)
  1. Examine whether the equation x^(2) + y^(2) - x - 4y + 7 = 0 represents...

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  2. Find the equation of the circle passing through (6, -5) and having cen...

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  3. Find the centre and radius of each of the following circles : 4x^(2)...

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  4. Find the centre and radius of each of the following circles : x^(2) ...

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  5. Find the centre and radius of each of the following circles : 3(x^(2...

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  6. Find the centre and radius of each of the following circles : (x-a)^...

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  7. Under the conditions ax^(2) + 2hxy + by^(2) + 2gx + 2fy + c = 0 will b...

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  8. Find the radius of the circle which passes through the origin and the ...

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  9. Find the equation of the circle for which the line segment joining the...

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  10. Find the position of the unit (-3, -2) with respect to the circle whos...

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  11. Find the equation of the diameter of the circle x^(2) + y^(2) - 4x + 6...

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  12. The straight line 3x-4y +7 = 0 is a tangent to the circle x^(2) + y^(2...

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  13. The length of diameter of the circle x^(2) + y^(2) + 4x - 7y - k = 0 i...

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  14. The coordinates of the centre of the circle 2x^(2)+2y^(2) + ax + by + ...

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  15. Find the equation of the circle which touches both the coordinates axe...

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  16. Find the parametric equation of the circle x^(2) + y^(2) + 4x - 8y - 5...

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  17. The parametric equations of a circle are, x = (1)/(2)(-3+4 cos theta),...

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  18. The equation of the in-circle of an equilateral triangle is x^(2) + y^...

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