The extremities of a diameter of a circl...

The extremities of a diameter of a circle are the points (4, -2) and (1, -3), find the equation of the circle. Also find the equation of that diameter of this circle which passes through the origin.

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The correct Answer is:

`x^(2) + y^(2) - 2x - y - 10 = 0` and x - 3y = 0

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