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When SO(2) is passed in acidified potass...

When `SO_(2)` is passed in acidified potassium dichromate solution, the oxidation number of S is changed from

A

`+4` to `+6`

B

`+6` to `+4`

C

`+4` to 0

D

`+4` to `+2`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(2)Cr_(2)O_(7)+overset(+4)(SO_(2))+H_(2)SO_(4) to `K_(2)overset(+6)(S)O_(4)+Cr_(2)(SO_(4))_(3)+H_(2)O+`
`+4` to `+6`
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