Number of moles of `K_(2)Cr_(2)O_(7)` can be reduced by 1 mole of `Sn^(2+)` ions is:

Options

A. `1//3`
B. 3
C. `1//6`
D. 6

Answer

A

Explanation

`(Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) to 2Cr^(3+)+7H_(2)O)^((1)/(3))`
`Sn^(2+)-2e^(-) to Sn^(4+)`
Hence `(1)/(3)Cr_(2)O_(7)^(2-)+(14)/(3)H^(+)+Sn^(2+) to (2)/(3)Cr^(3+)+(7)/(3)H_(2)O+Sn^(4+)`