Home
Class 11
CHEMISTRY
The equivalent weight of MnO(4)^(-) ion ...

The equivalent weight of `MnO_(4)^(-)` ion in acidic medium is

A

`31.6`

B

`23.8`

C

55

D

119

Text Solution

Verified by Experts

The correct Answer is:
B
`MnO_(4)^(-)+8n^(+)+5e^(-) to Mn^(2+)+4H_(2)O`
(In acidic medium)
`Mn^(+7) to Mn^(21)`(gain of 5 electrons)
`:.` Equivalent weight `=("Mol".wt. of MO_(4)^(-))/(5)`
`=(55+4xx16)/(5)`
`=(119)/(5)=23.8`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REDOX REACTIONS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|21 Videos

  • NATURE OF CHEMICAL BOND

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|50 Videos

  • S BLOCK ELEMENTS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|32 Videos

Similar Questions

Explore conceptually related problems

Find the ratio of equivalent weight of MnO_(4)^(-) in acidic and basic media

The equivalent weight of KMnO_(4) in (a) neutral medium, (b) acidic medium and (c ) alkaline medium is M//.. ( where M is mol.wt. of KMnO_(4) )

Knowledge Check

  • If the molecular weight of Ba(MnO_(4))_(2) is M , then the equivalent weight of Ba(MnO_(4))_(2) in acidic medium is

    A
    `M/5`
    B
    `M/10`
    C
    `M/3`
    D
    M

  • Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.

    A
    If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
    B
    If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
    C
    If Assertion is True but the Reason is False.
    D
    If both Assertion & Reason are False.

  • Equivalent weight of K_(2)Cr_(2)O_(4) in acidic medium is

    A
    `("Mol. wt")/(3)`
    B
    `("Mol. wt.")/(6)`
    C
    `("Mol. wt.")/(2)`
    D
    `"Mol.wt."`

    • Similar Questions

    Explore conceptually related problems

    A : Equivalent weight of KMnO_(4) in acidic medium is M/5 . R : In acidic medium 1 mol of MnO_(4)""^(-) gains 5 electron.

    The equivalent weight of KNnO_4 in acidic medium would be

    MnO_(4)^(-) on reduction in acid medium forms-

    Equivalent weight of KMnO_4 in acidic medium is

    Equivalent weight of KMnO_4 in acidic medium is

    Home
    Profile