The state of hybridization of the central atom is not the same as in the others :

Options

A. B in ` BF_(3)`
B. O in ` H_(3) OI^(+)`
C. N in ` NH_(3)`
D. P in ` PCl_(3)`

Answer

a

Explanation

(a) For ` BF_(3) , X = (1)/(2) [ 3 + 3 - 0 + 0 ] = 3`
` therefore ` Hybridization of B in ` BF_(3) = sp^(2)`
(b) For ` H_(3) O^(+) = (1)/(2) [ 6 + 3 - 1 + 0]=4`
` therefore ` Hybridization of O in ` H_(3)O^(+) sp^(3)`
(C) For ` NH_(3) = (1)/(2) [ 5 + 3 - 0 + 4 ] = 4 `
` therefore ` Hybridization of N in ` NH_(3) = sp^(3)`
(d) Hybridization of P in `PCl_(3) = sp^(3)` .
Thus , option (a) is correct .